5n^2-n-490=0

Solution for 5n^2-n-490=0 equation:

5n^2-n-490=0

We add all the numbers together, and all the variables

5n^2-1n-490=0

a = 5; b = -1; c = -490;
Δ = b2-4ac
Δ = -12-4·5·(-490)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-99}{2*5}=\frac{-98}{10}
=-9+4/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+99}{2*5}=\frac{100}{10}
=10
$